1000+ Quantitave Aptitude Questions Answer PDF For ALL Competitive Exams


1000+ Quantitave Aptitude Questions Answer PDF

This PDF Notes Contains 1000+ Quantitave Aptitude Questions Answer PDF – UPSC Notes, SSC Notes

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1. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A. 120 metres
B. 180 metres
C. 324 metres
D. 150 metres

Answer: Option D


Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

 Length of the train = 50 x 9 m = 150 m.

2. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A. 45 km/hr
B. 50 km/hr
C. 54 km/hr
D. 55 km/hr

Answer: Option B


Speed of the train relative to man = 125 m/sec
   = 25 m/sec.
   = 25 x 18 km/hr
2 5

= 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

 x – 5 = 45          x = 50 km/hr.

3. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A. 200 m
B. 225 m
C. 245 m
D. 250 m

Answer: Option C


Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

 2(130 + x) = 750

 x = 245 m.

4. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A. 1 : 3
B. 3 : 2
C. 3 : 4
D. None of these

Answer: Option B


Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23

 27x + 17y = 23x + 23y

 4x = 6y

x = 3 .
y 2

5. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A. 120 m
B. 240 m
C. 300 m
D. None of these

Answer: Option B


Speed = 54 x 5 m/sec = 15 m/sec.

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15

 x + 300 = 540

 x = 240 m.

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